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Manual Pages for UNIX Darwin command on man perldsc

PERLDSC(1) Perl Programmers Reference Guide PERLDSC(1)

NAME

perldsc - Perl Data Structures Cookbook

DESCRIPTION

The single feature most sorely lacking in the Perl programming language prior to its 5.0 release was complex data structures. Even without direct language support, some valiant programmers did manage to emulate them, but it was hard work and not for the faint of heart. You could

occasionally get away with the $m{$AoA,$b} notation borrowed from aawwkk

in which the keys are actually more like a single concatenated string

"$AoA$b", but traversal and sorting were difficult. More desperate

programmers even hacked Perl's internal symbol table directly, a strat-

egy that proved hard to develop and maintain-to put it mildly.

The 5.0 release of Perl let us have complex data structures. You may now write something like this and all of a sudden, you'd have an array with three dimensions!

for $x (1 .. 10) {

for $y (1 .. 10) {

for $z (1 .. 10) {

$AoA[$x][$y][$z] =

$x ** $y + $z;

} } }

Alas, however simple this may appear, underneath it's a much more elab-

orate construct than meets the eye! How do you print it out? Why can't you say just "print @AoA"? How do you sort it? How can you pass it to a function or get one of these back from a function? Is it an object? Can you save it to disk to read back later? How do you access whole rows or columns of that matrix? Do all the values have to be numeric?

As you see, it's quite easy to become confused. While some small por-

tion of the blame for this can be attributed to the reference-based

implementation, it's really more due to a lack of existing documenta-

tion with examples designed for the beginner. This document is meant to be a detailed but understandable treatment of the many different sorts of data structures you might want to develop. It should also serve as a cookbook of examples. That way, when you need to create one of these complex data structures, you can just

pinch, pilfer, or purloin a drop-in example from here.

Let's look at each of these possible constructs in detail. There are separate sections on each of the following: * arrays of arrays * hashes of arrays * arrays of hashes * hashes of hashes * more elaborate constructs But for now, let's look at general issues common to all these types of data structures. REFERENCES The most important thing to understand about all data structures in

Perl - including multidimensional arrays-is that even though they

might appear otherwise, Perl @ARRAYs and %HASHes are all internally

one-dimensional. They can hold only scalar values (meaning a string,

number, or a reference). They cannot directly contain other arrays or hashes, but instead contain references to other arrays or hashes. You can't use a reference to an array or hash in quite the same way that you would a real array or hash. For C or C++ programmers unused to distinguishing between arrays and pointers to the same, this can be

confusing. If so, just think of it as the difference between a struc-

ture and a pointer to a structure. You can (and should) read more about references in the perlref(1) man page. Briefly, references are rather like pointers that know what they

point to. (Objects are also a kind of reference, but we won't be need-

ing them right away-if ever.) This means that when you have something

which looks to you like an access to a two-or-more-dimensional array

and/or hash, what's really going on is that the base type is merely a

one-dimensional entity that contains references to the next level.

It's just that you can use it as though it were a two-dimensional one.

This is actually the way almost all C multidimensional arrays work as well.

$array[7][12] # array of arrays

$array[7]{string} # array of hashes

$hash{string}[7] # hash of arrays

$hash{string}{'another string'} # hash of hashes

Now, because the top level contains only references, if you try to print out your array in with a simple print() function, you'll get something that doesn't look very nice, like this: @AoA = ( [2, 3], [4, 5, 7], [0] );

print $AoA[1][2];

7 print @AoA; ARRAY(0x83c38)ARRAY(0x8b194)ARRAY(0x8b1d0)

That's because Perl doesn't (ever) implicitly dereference your vari-

ables. If you want to get at the thing a reference is referring to,

then you have to do this yourself using either prefix typing indica-

tors, like "${$blah}", "@{$blah}", "@{$blah[$i]}", or else postfix

pointer arrows, like "$a->[3]", "$h->{fred}", or even

"$ob->method()->[3]".

CCOOMMMMOONN MMIISSTTAAKKEESS The two most common mistakes made in constructing something like an array of arrays is either accidentally counting the number of elements or else taking a reference to the same memory location repeatedly. Here's the case where you just get the count instead of a nested array:

for $i (1..10) {

@array = somefunc($i);

$AoA[$i] = @array; # WRONG!

}

That's just the simple case of assigning an array to a scalar and get-

ting its element count. If that's what you really and truly want, then you might do well to consider being a tad more explicit about it, like this:

for $i (1..10) {

@array = somefunc($i);

$counts[$i] = scalar @array;

} Here's the case of taking a reference to the same memory location again and again:

for $i (1..10) {

@array = somefunc($i);

$AoA[$i] = \@array; # WRONG!

} So, what's the big problem with that? It looks right, doesn't it? After all, I just told you that you need an array of references, so by golly, you've made me one!

Unfortunately, while this is true, it's still broken. All the refer-

ences in @AoA refer to the very same place, and they will therefore all

hold whatever was last in @array! It's similar to the problem demon-

strated in the following C program:

#include

main() { struct passwd *getpwnam(), *rp, *dp; rp = getpwnam("root"); dp = getpwnam("daemon");

printf("daemon name is %s\nroot name is %s\n",

dp->pwname, rp->pwname);

} Which will print daemon name is daemon root name is daemon

The problem is that both "rp" and "dp" are pointers to the same loca-

tion in memory! In C, you'd have to remember to malloc() yourself some new memory. In Perl, you'll want to use the array constructor "[]" or the hash constructor "{}" instead. Here's the right way to do the preceding broken code fragments:

for $i (1..10) {

@array = somefunc($i);

$AoA[$i] = [ @array ];

} The square brackets make a reference to a new array with a copy of what's in @array at the time of the assignment. This is what you want. Note that this will produce something similar, but it's much harder to read:

for $i (1..10) {

@array = 0 .. $i;

@{$AoA[$i]} = @array;

}

Is it the same? Well, maybe so-and maybe not. The subtle difference

is that when you assign something in square brackets, you know for sure

it's always a brand new reference with a new copy of the data. Some-

thing else could be going on in this new case with the "@{$AoA[$i]}}"

dereference on the left-hand-side of the assignment. It all depends on

whether $AoA[$i] had been undefined to start with, or whether it

already contained a reference. If you had already populated @AoA with references, as in

$AoA[3] = \@anotherarray;

Then the assignment with the indirection on the left-hand-side would

use the existing reference that was already there:

@{$AoA[3]} = @array;

Of course, this would have the "interesting" effect of clobbering @anotherarray. (Have you ever noticed how when a programmer says something is "interesting", that rather than meaning "intriguing",

they're disturbingly more apt to mean that it's "annoying", "diffi-

cult", or both? :-)

So just remember always to use the array or hash constructors with "[]"

or "{}", and you'll be fine, although it's not always optimally effi-

cient.

Surprisingly, the following dangerous-looking construct will actually

work out fine:

for $i (1..10) {

my @array = somefunc($i);

$AoA[$i] = \@array;

}

That's because my() is more of a run-time statement than it is a com-

pile-time declaration per se. This means that the my() variable is

remade afresh each time through the loop. So even though it looks as though you stored the same variable reference each time, you actually did not! This is a subtle distinction that can produce more efficient

code at the risk of misleading all but the most experienced of program-

mers. So I usually advise against teaching it to beginners. In fact, except for passing arguments to functions, I seldom like to see the

gimme-a-reference operator (backslash) used much at all in code.

Instead, I advise beginners that they (and most of the rest of us) should try to use the much more easily understood constructors "[]" and "{}" instead of relying upon lexical (or dynamic) scoping and hidden

reference-counting to do the right thing behind the scenes.

In summary:

$AoA[$i] = [ @array ]; # usually best

$AoA[$i] = \@array; # perilous; just how my() was that array?

@{ $AoA[$i] } = @array; # way too tricky for most programmers

CCAAVVEEAATT OONN PPRREECCEEDDEENNCCEE

Speaking of things like "@{$AoA[$i]}", the following are actually the

same thing:

$aref->[2][2] # clear

$$aref[2][2] # confusing

That's because Perl's precedence rules on its five prefix dereferencers

(which look like someone swearing: "$ @ * % &") make them bind more

tightly than the postfix subscripting brackets or braces! This will no doubt come as a great shock to the C or C++ programmer, who is quite accustomed to using *a[i] to mean what's pointed to by the i'th element

of "a". That is, they first take the subscript, and only then derefer-

ence the thing at that subscript. That's fine in C, but this isn't C.

The seemingly equivalent construct in Perl, $$aref[$i] first does the

deref of $aref, making it take $aref as a reference to an array, and

then dereference that, and finally tell you the i'th value of the array

pointed to by $AoA. If you wanted the C notion, you'd have to write

"${$AoA[$i]}" to force the $AoA[$i] to get evaluated first before the

leading "$" dereferencer.

WWHHYY YYOOUU SSHHOOUULLDD AALLWWAAYYSS ""uussee ssttrriicctt"" If this is starting to sound scarier than it's worth, relax. Perl has some features to help you avoid its most common pitfalls. The best way to avoid getting confused is to start every program like this:

#!/usr/bin/perl -w

use strict; This way, you'll be forced to declare all your variables with my() and also disallow accidental "symbolic dereferencing". Therefore if you'd done this:

my $aref = [

[ "fred", "barney", "pebbles", "bambam", "dino", ], [ "homer", "bart", "marge", "maggie", ], [ "george", "jane", "elroy", "judy", ], ];

print $aref[2][2];

The compiler would immediately flag that as an error at compile time, because you were accidentally accessing @aref, an undeclared variable, and it would thereby remind you to write instead:

print $aref->[2][2]

DDEEBBUUGGGGIINNGG Before version 5.002, the standard Perl debugger didn't do a very nice job of printing out complex data structures. With 5.002 or above, the debugger includes several new features, including command line editing as well as the "x" command to dump out complex data structures. For

example, given the assignment to $AoA above, here's the debugger out-

put:

DB<1> x $AoA

$AoA = ARRAY(0x13b5a0)

0 ARRAY(0x1f0a24) 0 'fred' 1 'barney' 2 'pebbles' 3 'bambam' 4 'dino' 1 ARRAY(0x13b558) 0 'homer' 1 'bart' 2 'marge' 3 'maggie' 2 ARRAY(0x13b540) 0 'george' 1 'jane' 2 'elroy' 3 'judy' CCOODDEE EEXXAAMMPPLLEESS

Presented with little comment (these will get their own manpages some-

day) here are short code examples illustrating access of various types of data structures. AARRRRAAYYSS OOFF AARRRRAAYYSS DDeeccllaarraattiioonn ooff aann AARRRRAAYY OOFF AARRRRAAYYSS @AoA = ( [ "fred", "barney" ], [ "george", "jane", "elroy" ], [ "homer", "marge", "bart" ], ); GGeenneerraattiioonn ooff aann AARRRRAAYY OOFF AARRRRAAYYSS

# reading from file

while ( <> ) { push @AoA, [ split ]; }

# calling a function

for $i ( 1 .. 10 ) {

$AoA[$i] = [ somefunc($i) ];

}

# using temp vars

for $i ( 1 .. 10 ) {

@tmp = somefunc($i);

$AoA[$i] = [ @tmp ];

}

# add to an existing row

push @{ $AoA[0] }, "wilma", "betty";

AAcccceessss aanndd PPrriinnttiinngg ooff aann AARRRRAAYY OOFF AARRRRAAYYSS

# one element

$AoA[0][0] = "Fred";

# another element

$AoA[1][1] =~ s/(\w)/\u$1/;

# print the whole thing with refs

for $aref ( @AoA ) {

print "\t [ @$aref ],\n";

}

# print the whole thing with indices

for $i ( 0 .. $#AoA ) {

print "\t [ @{$AoA[$i]} ],\n";

}

# print the whole thing one at a time

for $i ( 0 .. $#AoA ) {

for $j ( 0 .. $#{ $AoA[$i] } ) {

print "elt $i $j is $AoA[$i][$j]\n";

} } HHAASSHHEESS OOFF AARRRRAAYYSS DDeeccllaarraattiioonn ooff aa HHAASSHH OOFF AARRRRAAYYSS

%HoA = (

flintstones => [ "fred", "barney" ], jetsons => [ "george", "jane", "elroy" ], simpsons => [ "homer", "marge", "bart" ], ); GGeenneerraattiioonn ooff aa HHAASSHH OOFF AARRRRAAYYSS

# reading from file

# flintstones: fred barney wilma dino

while ( <> ) { next unless s/^(.*?):\s*//;

$HoA{$1} = [ split ];

}

# reading from file; more temps

# flintstones: fred barney wilma dino

while ( $line = <> ) {

($who, $rest) = split /:\s*/, $line, 2;

@fields = split ' ', $rest;

$HoA{$who} = [ @fields ];

}

# calling a function that returns a list

for $group ( "simpsons", "jetsons", "flintstones" ) {

$HoA{$group} = [ getfamily($group) ];

}

# likewise, but using temps

for $group ( "simpsons", "jetsons", "flintstones" ) {

@members = getfamily($group);

$HoA{$group} = [ @members ];

}

# append new members to an existing family

push @{ $HoA{"flintstones"} }, "wilma", "betty";

AAcccceessss aanndd PPrriinnttiinngg ooff aa HHAASSHH OOFF AARRRRAAYYSS

# one element

$HoA{flintstones}[0] = "Fred";

# another element

$HoA{simpsons}[1] =~ s/(\w)/\u$1/;

# print the whole thing

foreach $family ( keys %HoA ) {

print "$family: @{ $HoA{$family} }\n"

}

# print the whole thing with indices

foreach $family ( keys %HoA ) {

print "family: ";

foreach $i ( 0 .. $#{ $HoA{$family} } ) {

print " $i = $HoA{$family}[$i]";

} print "\n"; }

# print the whole thing sorted by number of members

foreach $family ( sort { @{$HoA{$b}} <=> @{$HoA{$a}} } keys %HoA ) {

print "$family: @{ $HoA{$family} }\n"

}

# print the whole thing sorted by number of members and name

foreach $family ( sort {

@{$HoA{$b}} <=> @{$HoA{$a}}

||

$a cmp $b

} keys %HoA )

{

print "$family: ", join(", ", sort @{ $HoA{$family} }), "\n";

} AARRRRAAYYSS OOFF HHAASSHHEESS DDeeccllaarraattiioonn ooff aann AARRRRAAYY OOFF HHAASSHHEESS @AoH = ( { Lead => "fred", Friend => "barney", }, { Lead => "george", Wife => "jane", Son => "elroy", }, { Lead => "homer", Wife => "marge", Son => "bart", } ); GGeenneerraattiioonn ooff aann AARRRRAAYY OOFF HHAASSHHEESS

# reading from file

# format: LEAD=fred FRIEND=barney

while ( <> ) {

$rec = {};

for $field ( split ) {

($key, $value) = split /=/, $field;

$rec->{$key} = $value;

}

push @AoH, $rec;

}

# reading from file

# format: LEAD=fred FRIEND=barney

# no temp

while ( <> ) { push @AoH, { split /[\s+=]/ }; }

# calling a function that returns a key/value pair list, like

# "lead","fred","daughter","pebbles"

while ( %fields = getnextpairset() ) {

push @AoH, { %fields };

}

# likewise, but using no temp vars

while (<>) {

push @AoH, { parsepairs($) };

}

# add key/value to an element

$AoH[0]{pet} = "dino";

$AoH[2]{pet} = "santa's little helper";

AAcccceessss aanndd PPrriinnttiinngg ooff aann AARRRRAAYY OOFF HHAASSHHEESS

# one element

$AoH[0]{lead} = "fred";

# another element

$AoH[1]{lead} =~ s/(\w)/\u$1/;

# print the whole thing with refs

for $href ( @AoH ) {

print "{ ";

for $role ( keys %$href ) {

print "$role=$href->{$role} ";

} print "}\n"; }

# print the whole thing with indices

for $i ( 0 .. $#AoH ) {

print "$i is { ";

for $role ( keys %{ $AoH[$i] } ) {

print "$role=$AoH[$i]{$role} ";

} print "}\n"; }

# print the whole thing one at a time

for $i ( 0 .. $#AoH ) {

for $role ( keys %{ $AoH[$i] } ) {

print "elt $i $role is $AoH[$i]{$role}\n";

} } HHAASSHHEESS OOFF HHAASSHHEESS DDeeccllaarraattiioonn ooff aa HHAASSHH OOFF HHAASSHHEESS

%HoH = (

flintstones => { lead => "fred", pal => "barney", }, jetsons => { lead => "george", wife => "jane", "his boy" => "elroy", }, simpsons => { lead => "homer", wife => "marge", kid => "bart", }, ); GGeenneerraattiioonn ooff aa HHAASSHH OOFF HHAASSHHEESS

# reading from file

# flintstones: lead=fred pal=barney wife=wilma pet=dino

while ( <> ) { next unless s/^(.*?):\s*//;

$who = $1;

for $field ( split ) {

($key, $value) = split /=/, $field;

$HoH{$who}{$key} = $value;

}

# reading from file; more temps

while ( <> ) { next unless s/^(.*?):\s*//;

$who = $1;

$rec = {};

$HoH{$who} = $rec;

for $field ( split ) {

($key, $value) = split /=/, $field;

$rec->{$key} = $value;

} }

# calling a function that returns a key,value hash

for $group ( "simpsons", "jetsons", "flintstones" ) {

$HoH{$group} = { getfamily($group) };

}

# likewise, but using temps

for $group ( "simpsons", "jetsons", "flintstones" ) {

%members = getfamily($group);

$HoH{$group} = { %members };

}

# append new members to an existing family

%newfolks = (

wife => "wilma", pet => "dino", );

for $what (keys %newfolks) {

$HoH{flintstones}{$what} = $newfolks{$what};

} AAcccceessss aanndd PPrriinnttiinngg ooff aa HHAASSHH OOFF HHAASSHHEESS

# one element

$HoH{flintstones}{wife} = "wilma";

# another element

$HoH{simpsons}{lead} =~ s/(\w)/\u$1/;

# print the whole thing

foreach $family ( keys %HoH ) {

print "$family: { ";

for $role ( keys %{ $HoH{$family} } ) {

print "$role=$HoH{$family}{$role} ";

} print "}\n"; }

# print the whole thing somewhat sorted

foreach $family ( sort keys %HoH ) {

print "$family: { ";

for $role ( sort keys %{ $HoH{$family} } ) {

print "$role=$HoH{$family}{$role} ";

} print "}\n"; }

# print the whole thing sorted by number of members

foreach $family ( sort { keys %{$HoH{$b}} <=> keys %{$HoH{$a}} } keys %HoH ) {

print "$family: { ";

for $role ( sort keys %{ $HoH{$family} } ) {

print "$role=$HoH{$family}{$role} ";

} print "}\n"; }

# establish a sort order (rank) for each role

$i = 0;

for ( qw(lead wife son daughter pal pet) ) { $rank{$} = ++$i }

# now print the whole thing sorted by number of members

foreach $family ( sort { keys %{ $HoH{$b} } <=> keys %{ $HoH{$a} } } keys %HoH ) {

print "$family: { ";

# and print these according to rank order

for $role ( sort { $rank{$a} <=> $rank{$b} } keys %{ $HoH{$family} } ) {

print "$role=$HoH{$family}{$role} ";

} print "}\n"; } MMOORREE EELLAABBOORRAATTEE RREECCOORRDDSS DDeeccllaarraattiioonn ooff MMOORREE EELLAABBOORRAATTEE RREECCOORRDDSS Here's a sample showing how to create and use a record whose fields are of many different sorts:

$rec = {

TEXT => $string,

SEQUENCE => [ @oldvalues ],

LOOKUP => { %sometable },

THATCODE => \&somefunction,

THISCODE => sub { $[0] ** $[1] },

HANDLE => \*STDOUT, };

print $rec->{TEXT};

print $rec->{SEQUENCE}[0];

$last = pop @ { $rec->{SEQUENCE} };

print $rec->{LOOKUP}{"key"};

($firstk, $firstv) = each %{ $rec->{LOOKUP} };

$answer = $rec->{THATCODE}->($arg);

$answer = $rec->{THISCODE}->($arg1, $arg2);

# careful of extra block braces on fh ref

print { $rec->{HANDLE} } "a string\n";

use FileHandle;

$rec->{HANDLE}->autoflush(1);

$rec->{HANDLE}->print(" a string\n");

DDeeccllaarraattiioonn ooff aa HHAASSHH OOFF CCOOMMPPLLEEXX RREECCOORRDDSS

%TV = (

flintstones => { series => "flintstones", nights => [ qw(monday thursday friday) ], members => [ { name => "fred", role => "lead", age => 36, }, { name => "wilma", role => "wife", age => 31, }, { name => "pebbles", role => "kid", age => 4, }, ], }, jetsons => { series => "jetsons", nights => [ qw(wednesday saturday) ], members => [ { name => "george", role => "lead", age => 41, }, { name => "jane", role => "wife", age => 39, }, { name => "elroy", role => "kid", age => 9, }, ], }, simpsons => { series => "simpsons", nights => [ qw(monday) ], members => [ { name => "homer", role => "lead", age => 34, }, { name => "marge", role => "wife", age => 37, }, { name => "bart", role => "kid", age => 11, }, ], }, ); GGeenneerraattiioonn ooff aa HHAASSHH OOFF CCOOMMPPLLEEXX RREECCOORRDDSS

# reading from file

# this is most easily done by having the file itself be

# in the raw data format as shown above. perl is happy

# to parse complex data structures if declared as data, so

# sometimes it's easiest to do that

# here's a piece by piece build up

$rec = {};

$rec->{series} = "flintstones";

$rec->{nights} = [ finddays() ];

@members = ();

# assume this file in field=value syntax

while (<>) {

%fields = split /[\s=]+/;

push @members, { %fields };

}

$rec->{members} = [ @members ];

# now remember the whole thing

$TV{ $rec->{series} } = $rec;

###########################################################

# now, you might want to make interesting extra fields that

# include pointers back into the same data structure so if

# change one piece, it changes everywhere, like for example

# if you wanted a {kids} field that was a reference

# to an array of the kids' records without having duplicate

# records and thus update problems.

###########################################################

foreach $family (keys %TV) {

$rec = $TV{$family}; # temp pointer

@kids = ();

for $person ( @{ $rec->{members} } ) {

if ($person->{role} =~ /kid|son|daughter/) {

push @kids, $person;

} }

# REMEMBER: $rec and $TV{$family} point to same data!!

$rec->{kids} = [ @kids ];

}

# you copied the array, but the array itself contains pointers

# to uncopied objects. this means that if you make bart get

# older via

$TV{simpsons}{kids}[0]{age}++;

# then this would also change in

print $TV{simpsons}{members}[2]{age};

# because $TV{simpsons}{kids}[0] and $TV{simpsons}{members}[2]

# both point to the same underlying anonymous hash table

# print the whole thing

foreach $family ( keys %TV ) {

print "the $family";

print " is on during @{ $TV{$family}{nights} }\n";

print "its members are:\n";

for $who ( @{ $TV{$family}{members} } ) {

print " $who->{name} ($who->{role}), age $who->{age}\n";

}

print "it turns out that $TV{$family}{lead} has ";

print scalar ( @{ $TV{$family}{kids} } ), " kids named ";

print join (", ", map { $->{name} } @{ $TV{$family}{kids} } );

print "\n"; } DDaattaabbaassee TTiieess You cannot easily tie a multilevel data structure (such as a hash of hashes) to a dbm file. The first problem is that all but GDBM and

Berkeley DB have size limitations, but beyond that, you also have prob-

lems with how references are to be represented on disk. One experimen-

tal module that does partially attempt to address this need is the MLDBM module. Check your nearest CPAN site as described in perlmodlib for source code to MLDBM.

SEE ALSO

perlref(1), perllol(1), perldata(1), perlobj(1) AUTHOR Tom Christiansen Last update: Wed Oct 23 04:57:50 MET DST 1996

perl v5.8.6 2004-11-05 PERLDSC(1)




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